Created
June 4, 2015 19:14
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LeetCode - Palindrome Partitioning
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| public ArrayList<ArrayList<String>> partition(String s) { | |
| ArrayList<ArrayList<String>> ret = new ArrayList<ArrayList<String>>(); | |
| if(s == null || s.length()==0) return ret; | |
| helper(ret, s, new ArrayList<String>()); | |
| return ret; | |
| } | |
| public void helper(ArrayList<ArrayList<String>> ret, String s, ArrayList<String> lst){ | |
| if(s.length() == 0){ | |
| ret.add(new ArrayList<String>(lst)); | |
| return; | |
| } | |
| for(int i=1; i <= s.length(); i++){ // don't forget to consider "=" case | |
| String cur = s.substring(0, i); | |
| if(IsPalindrome(cur)){ | |
| lst.add(cur); | |
| helper(ret, s.substring(i), lst); | |
| lst.remove(lst.size()-1); | |
| } | |
| } | |
| } | |
| public boolean IsPalindrome(String str){ | |
| if(str == null || str.length() == 0) return false; | |
| int left = 0, right = str.length() - 1; | |
| while(left < right){ | |
| if(str.charAt(left) != str.charAt(right)){ | |
| return false; | |
| } | |
| left++; | |
| right--; | |
| } | |
| return true; | |
| } | |
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