Created
April 19, 2016 03:28
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LeetCode - Maximum Size Subarray Sum Equals k
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// Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead. | |
// Example 1: | |
// Given nums = [1, -1, 5, -2, 3], k = 3, | |
// return 4. (because the subarray [1, -1, 5, -2] sums to 3 and is the longest) | |
// Example 2: | |
// Given nums = [-2, -1, 2, 1], k = 1, | |
// return 2. (because the subarray [-1, 2] sums to 1 and is the longest) | |
// Follow Up: | |
// Can you do it in O(n) time? | |
public int maxSubArrayLen(int[] nums, int k) { | |
if(nums == null || nums.length == 0) return 0; | |
int[] sums = new int[nums.length + 1]; | |
Map<Integer, Integer> map = new HashMap<>(); | |
// map.put(0, -1); | |
for(int i = 0; i < nums.length; i++){ | |
sums[i+1] = sums[i] + nums[i]; | |
map.put(sums[i+1], i+1); | |
} | |
int max = Integer.MIN_VALUE; | |
for(int i = 0; i < sums.length; i++){ | |
int val = k + sums[i]; | |
if(map.containsKey(val)){ | |
max = Math.max(max, map.get(val) - i); | |
} | |
} | |
return max > 0 ? max : 0; | |
} |
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