Takes a number and adds five, complete with error handling

Gordon Input

#include <iostream>

using namespace std;

int main( int argc, char *argv[] )
{
	int number;

	// Go forever
	while( 1 )
	{
		// Take input
		cout << "Enter any number you want!: ";
		cin >> number;

		// Make sure input is numeric
		if( cin )
		{
			// Add 5
			number = number + 5;

			// Print output
			cout << number << endl; 
		}
		else // If the input is not numeric, show an error and clear stream
		{
			cout << "You didn't enter a number, silly!" << endl; 
			cin.clear();
			cin.ignore();
		}
	}

	return 0; // just because
}