Python print in C++ (kinda, without named arguments)

pyprint.cpp

// Written by Cooper H., released into the public domain or w/e license gist forces you to use
#include <iostream>

// thanks https://stackoverflow.com/questions/1657883/variable-number-of-arguments-in-c
template <typename T>
static void _print(const T & t) {
    std::cout << t;
}

template<typename T, typename... Args>
static void _print(const T & t, Args... args) {
    std::cout << t << " ";
    _print(args...);
}

template<typename... Args>
static void print(Args... args) {
    _print(args...);
    std::cout << std::endl;
}

// Example:
int main() {
    print("Hello World! A number:", 368-16/2, "A floating-point number:", 500.0/1234);
}