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March 8, 2016 15:04
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#!/usr/bin/env python | |
""" | |
Bytes-to-human / human-to-bytes converter. | |
Based on: http://goo.gl/kTQMs | |
Working with Python 2.x and 3.x. | |
Author: Giampaolo Rodola' <g.rodola [AT] gmail [DOT] com> | |
License: MIT | |
""" | |
# see: http://goo.gl/kTQMs | |
SYMBOLS = { | |
'customary' : ('B', 'K', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y'), | |
'customary_ext' : ('byte', 'kilo', 'mega', 'giga', 'tera', 'peta', 'exa', | |
'zetta', 'iotta'), | |
'iec' : ('Bi', 'Ki', 'Mi', 'Gi', 'Ti', 'Pi', 'Ei', 'Zi', 'Yi'), | |
'iec_ext' : ('byte', 'kibi', 'mebi', 'gibi', 'tebi', 'pebi', 'exbi', | |
'zebi', 'yobi'), | |
} | |
def bytes2human(n, format='%(value).1f %(symbol)s', symbols='customary'): | |
""" | |
Convert n bytes into a human readable string based on format. | |
symbols can be either "customary", "customary_ext", "iec" or "iec_ext", | |
see: http://goo.gl/kTQMs | |
>>> bytes2human(0) | |
'0.0 B' | |
>>> bytes2human(0.9) | |
'0.0 B' | |
>>> bytes2human(1) | |
'1.0 B' | |
>>> bytes2human(1.9) | |
'1.0 B' | |
>>> bytes2human(1024) | |
'1.0 K' | |
>>> bytes2human(1048576) | |
'1.0 M' | |
>>> bytes2human(1099511627776127398123789121) | |
'909.5 Y' | |
>>> bytes2human(9856, symbols="customary") | |
'9.6 K' | |
>>> bytes2human(9856, symbols="customary_ext") | |
'9.6 kilo' | |
>>> bytes2human(9856, symbols="iec") | |
'9.6 Ki' | |
>>> bytes2human(9856, symbols="iec_ext") | |
'9.6 kibi' | |
>>> bytes2human(10000, "%(value).1f %(symbol)s/sec") | |
'9.8 K/sec' | |
>>> # precision can be adjusted by playing with %f operator | |
>>> bytes2human(10000, format="%(value).5f %(symbol)s") | |
'9.76562 K' | |
""" | |
n = int(n) | |
if n < 0: | |
raise ValueError("n < 0") | |
symbols = SYMBOLS[symbols] | |
prefix = {} | |
for i, s in enumerate(symbols[1:]): | |
prefix[s] = 1 << (i+1)*10 | |
for symbol in reversed(symbols[1:]): | |
if n >= prefix[symbol]: | |
value = float(n) / prefix[symbol] | |
return format % locals() | |
return format % dict(symbol=symbols[0], value=n) | |
def human2bytes(s): | |
""" | |
Attempts to guess the string format based on default symbols | |
set and return the corresponding bytes as an integer. | |
When unable to recognize the format ValueError is raised. | |
>>> human2bytes('0 B') | |
0 | |
>>> human2bytes('1 K') | |
1024 | |
>>> human2bytes('1 M') | |
1048576 | |
>>> human2bytes('1 Gi') | |
1073741824 | |
>>> human2bytes('1 tera') | |
1099511627776 | |
>>> human2bytes('0.5kilo') | |
512 | |
>>> human2bytes('0.1 byte') | |
0 | |
>>> human2bytes('1 k') # k is an alias for K | |
1024 | |
>>> human2bytes('12 foo') | |
Traceback (most recent call last): | |
... | |
ValueError: can't interpret '12 foo' | |
""" | |
init = s | |
num = "" | |
while s and s[0:1].isdigit() or s[0:1] == '.': | |
num += s[0] | |
s = s[1:] | |
num = float(num) | |
letter = s.strip() | |
for name, sset in SYMBOLS.items(): | |
if letter in sset: | |
break | |
else: | |
if letter == 'k': | |
# treat 'k' as an alias for 'K' as per: http://goo.gl/kTQMs | |
sset = SYMBOLS['customary'] | |
letter = letter.upper() | |
else: | |
raise ValueError("can't interpret %r" % init) | |
prefix = {sset[0]:1} | |
for i, s in enumerate(sset[1:]): | |
prefix[s] = 1 << (i+1)*10 | |
return int(num * prefix[letter]) | |
if __name__ == "__main__": | |
import doctest | |
doctest.testmod() |
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