Created
August 11, 2013 23:25
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Given an unsorted array of integers, find the length of the longest consecutive elements sequence. | |
For example, | |
Given [100, 4, 200, 1, 3, 2], | |
The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4. | |
Your algorithm should run in O(n) complexity. |
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import java.util.HashMap; | |
public class Solution { | |
public int longestConsecutive(int[] num) { | |
// Start typing your Java solution below | |
// DO NOT write main() function | |
HashMap<Integer, Integer> map = new HashMap<Integer, Integer>(); | |
for(int i = 0; i < num.length; i++){ | |
int n = num[i]; | |
if(map.containsKey(n)) continue; | |
if(map.containsKey(n - 1) || map.containsKey(n + 1)){ | |
int value = 1; | |
int beforeOffset = 0; | |
if(map.containsKey(n - 1)){ | |
beforeOffset = map.get(n - 1); | |
value += map.get(n - 1); | |
map.put(n - beforeOffset, value); | |
map.put(n, value); | |
} | |
if(map.containsKey(n + 1)){ | |
value += map.get(n + 1); | |
map.put(n + map.get(n + 1), value); | |
map.put(n, value); | |
} | |
if(map.containsKey(n - 1)) map.put(n - beforeOffset, value); | |
} | |
else map.put(n, 1); | |
} | |
int max = 0; | |
for(Integer len: map.values()){ | |
if(len > max) max = len; | |
} | |
return max; | |
} | |
} |
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