Created
August 23, 2013 17:55
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Given an array where elements are sorted in ascending order, convert it to a height balanced BST. |
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/** | |
* Definition for binary tree | |
* public class TreeNode { | |
* int val; | |
* TreeNode left; | |
* TreeNode right; | |
* TreeNode(int x) { val = x; } | |
* } | |
*/ | |
public class Solution { | |
public TreeNode sortedArrayToBST(int[] num) { | |
// Start typing your Java solution below | |
// DO NOT write main() function | |
return build(num, 0, num.length - 1); | |
} | |
public TreeNode build(int[] num, int begin, int end){ | |
if(begin > end) return null; | |
int mid = (begin + end) / 2; | |
TreeNode node = new TreeNode(num[mid]); | |
node.left = build(num, begin, mid - 1); | |
node.right = build(num, mid + 1, end); | |
return node; | |
} | |
} |
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