Created
November 11, 2013 04:19
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Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. | |
For example, | |
Given 1->2->3->3->4->4->5, return 1->2->5. | |
Given 1->1->1->2->3, return 2->3. |
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/** | |
* Definition for singly-linked list. | |
* public class ListNode { | |
* int val; | |
* ListNode next; | |
* ListNode(int x) { | |
* val = x; | |
* next = null; | |
* } | |
* } | |
*/ | |
public class Solution { | |
public ListNode deleteDuplicates(ListNode head) { | |
// IMPORTANT: Please reset any member data you declared, as | |
// the same Solution instance will be reused for each test case. | |
if(head == null) return null; | |
ListNode result = null; | |
ListNode begin = null; | |
while(head != null){ | |
int num = head.val; | |
if(head.next != null && head.next.val == num){ | |
while(head != null && head.val == num) head = head.next; | |
} | |
else{ | |
if(result == null){ | |
result = head; | |
begin = result; | |
} | |
else{ | |
result.next = head; | |
result = result.next; | |
} | |
head = head.next; | |
result.next = null; | |
} | |
} | |
return begin; | |
} | |
} |
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