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@chinchang
Last active September 7, 2023 02:39
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Function to convert XML to JSON
/**
* Changes XML to JSON
* Modified version from here: http://davidwalsh.name/convert-xml-json
* @param {string} xml XML DOM tree
*/
function xmlToJson(xml) {
// Create the return object
var obj = {};
if (xml.nodeType == 1) {
// element
// do attributes
if (xml.attributes.length > 0) {
obj["@attributes"] = {};
for (var j = 0; j < xml.attributes.length; j++) {
var attribute = xml.attributes.item(j);
obj["@attributes"][attribute.nodeName] = attribute.nodeValue;
}
}
} else if (xml.nodeType == 3) {
// text
obj = xml.nodeValue;
}
// do children
// If all text nodes inside, get concatenated text from them.
var textNodes = [].slice.call(xml.childNodes).filter(function(node) {
return node.nodeType === 3;
});
if (xml.hasChildNodes() && xml.childNodes.length === textNodes.length) {
obj = [].slice.call(xml.childNodes).reduce(function(text, node) {
return text + node.nodeValue;
}, "");
} else if (xml.hasChildNodes()) {
for (var i = 0; i < xml.childNodes.length; i++) {
var item = xml.childNodes.item(i);
var nodeName = item.nodeName;
if (typeof obj[nodeName] == "undefined") {
obj[nodeName] = xmlToJson(item);
} else {
if (typeof obj[nodeName].push == "undefined") {
var old = obj[nodeName];
obj[nodeName] = [];
obj[nodeName].push(old);
}
obj[nodeName].push(xmlToJson(item));
}
}
}
return obj;
}
/*
Usage:
1. If you have an XML file URL:
const response = await fetch('file_url');
const xmlString = await response.text();
var XmlNode = new DOMParser().parseFromString(xmlString, 'text/xml');
xmlToJson(XmlNode);
2. If you have an XML as string:
var XmlNode = new DOMParser().parseFromString(yourXmlString, 'text/xml');
xmlToJson(XmlNode);
3. If you have the XML as a DOM Node:
xmlToJson(YourXmlNode);
*/
@lhalvesf
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thank you!

@Qasim118
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I am facing an error " cannot convert undefined or null to object " in line 23

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