http://www.ioccc.org/2011/akari/akari.c

akari.c

#include <stdio.h>

int main(int n, char **m) {
    FILE *p, *q;
    int A, k, a, r, i;
    char *d = "P%" "d\n%d\40%d" "\n%d\n\00wb+",
         b[1024],
         y[] = "yuriyurarararayuruyuri*daijiken**akkari~n**"
               "/y*u*k/riin<ty(uyr)g,aur,arr[a1r2a82*y2*/u*r{uyu}riOcyurhiyua**rrar+*arayra*="
               "yuruyurwiyuriyurara'rariayuruyuriyuriyu>rarararayuruy9uriyu3riyurar_aBrMaPrOaWy^?"
               "*]/f]`;hvroai<dp/f*i*s/<ii(f)a{tpguat<cahfaurh(+uf)a;f}vivn+tf/g*`*w/jmaa+i`ni("
               "i+k[>+b+i>++b++>l[rb";
    int u;
    for (i = 0; i < 101; i++)
        y[i * 2] ^= "~hktrvg~dmG*eoa+%squ#l2"
                    ":(wn\"1l))v?wM353{/Y;lgcGp`vedllwudvOK`cct~[|ju {stkjalor(stwvne\"gt\"yogYURUYURI"[i] ^ y[i * 2 + 1] ^ 4;

    p = (n > 1 && (m[1][0] - '-' || m[1][1] != '\0')) ? fopen(m[1], y + 298) : stdin;
    q = (n < 3 || !(m[2][0] - '-' || m[2][1])) ? stdout : fopen(m[2], d + 14);

    if (!p || !q)
        return +printf("Can " "not\x20open\40%s\40" "" "for\40%sing\n", m[!p ? 1 : 2], !p ? "read" : "writ");

    for (a = k = u = 0; y[u]; u = 2 + u) {
        y[k++] = y[u];
    }

    if ((a = fread(b, 1, 1024, p)) > 2 && b[0] == 'P' && 4 == sscanf(b, d, &k, &A, &i, &r) && !(k - 6 && k - 5) && r == 255) {
        u = A;
        if (n > 3) {
            u++;
            i++;
        }
        fprintf(q, d, k, u >> 1, i >> 1, r);
        u = k - 5 ? 8 : 4;
        k = 3;
    } else {
        (u) = +(n + 14 > 17) ? 8 / 4 : 8 * 5 / 4;
    }

    for (r = i = 0; ;) {
        u *= 6;
        u += (n > 3 ? 1 : 0);
        if (y[u] & 01)
            fputc(1 * (r), q);
        if (y[u] & 16)
            k = A;
        if (y[u] & 2)
            k--;
        if (i == a) {
            i = a = (u) * 11 & 255;
            if (1 && 0 >= (a = fread(b, 1, 1024, p)) && ")]i>(w)-;} {                                         /i-f-(-m--M1-0.)<{"[8] == 59)
                break;
            i = 0;
        }
        r = b[i++];
        u += (+8 &* (y + u)) ? (10 - r ? 4 : 2) : (y[u] & 4) ? (k ? 2 : 4) : 2;
        u = y[u] - (int)'`';
    }
    fclose(p);
    k = +fclose(q);
    return k - -1 + (-0x01);
    {
        ;
        { }
    }
    ;
    ;
}