JS: Sort a JavaScript object by key in alphabetical order case insensitive. Thanks to Arne Martin Aurlien and Ivan Krechetov for inspiration. #snippet

sortObj.js

/**
 * Sort JavaScript Object
 * CF Webtools : Chris Tierney
 * obj = object to sort
 * order = 'asc' or 'desc'
 */
function sortObj( obj, order ) {
	"use strict";

	var key,
		tempArry = [],
		i,
		tempObj = {};

	for ( key in obj ) {
		tempArry.push(key);
	}

	tempArry.sort(
		function(a, b) {
			return a.toLowerCase().localeCompare( b.toLowerCase() );
		}
	);

	if( order === 'desc' ) {
		for ( i = tempArry.length - 1; i >= 0; i-- ) {
			tempObj[ tempArry[i] ] = obj[ tempArry[i] ];
		}
	} else {
		for ( i = 0; i < tempArry.length; i++ ) {
			tempObj[ tempArry[i] ] = obj[ tempArry[i] ];
		}
	}

	return tempObj;
}

@farksid that didn't work perfectly. This seems to do it:

function sortObjKeysAlphabetically(obj) {
  var ordered = {};
 Object.keys(obj).sort().forEach(function(key) {
   ordered[key] = obj[key];
 });
return ordered;
}

var sortedObj = sortObjKeysAlphabetically(unorderedObj);

This code sorts objects deeply and will also handle arrays:

const alphaSort = (object: any): object => {
  if (object !== null && typeof object === "object") {
    return Object.keys(object)
      .sort((a, b) => sortByAlphabet(a.toLowerCase(), b.toLowerCase()))
      .reduce((result: object, key: string) => {
        result[key] = object[key];
        if (Array.isArray(result[key])) {
          result[key] = result[key].map((obj: any) => alphaSort(obj));
        }
        return result;
      }, {});
  } else if (Array.isArray(object)) {
    return object.map(obj => alphaSort(obj));
  } else {
    return object;
  }
};

// function
sortArr(a, b) {
var textA = a.keyName.toUpperCase();
var textB = b.keyName.toUpperCase();
return (textA < textB) ? -1 : (textA > textB) ? 1 : 0;
}

// calling function (here array is your array item)

array.sort(this.sortArr);

const sortObjKeysAlphabetically = (obj) => Object.fromEntries(Object.entries(obj).sort());