A function to get fractional age for my conky

age.lua

function conky_get_age(year, month, day)
 if conky_window == nil then
  return
 end
 daystoday = os.date("%j")
 daysatbirth = os.date("%j", os.time{year=year, month=month, day=day})
 yearsold = os.date("%Y") - os.date("%Y", os.time{year=year, month=month, day=day})
 if daysatbirth > daystoday then
  yearsold = math.floor(yearsold - 1)
  dayssince = (365 - daysatbirth) + daystoday
 else
  dayssince = daystoday - daysatbirth
 end
 if dayssince == 0 then
  return string.format("%d", yearsold).." years old."
 end
 
 function isin(...)
 one, two, three, four, five, six = ...
  return isle(one, two, three, four) and islt(three, four, five, six)
 end
	
 function islt(...)
  one, two, three, four = ...
  return (one * four) < (two * three)
 end

 function isle(...)
  one, two, three, four = ...
  return (one * four) <= (two * three)
 end

 lown = 0
 lowd = 1
 highn = 1
 highd = 0

 while 1 do
  num = lown + highn
  den = lowd + highd
  if isin(dayssince, 365, num, den, (dayssince + 1), 365) then
   return string.format("%d", yearsold).." "..num.."/"..den.." years old."
  elseif islt(num, den, dayssince, 365) then
   lown = num
   lowd = den
  elseif isle((dayssince + 1), 365, num, den) then
   highn = num
   highd = den
  end
 end
end