Script for finding common following of your following | Soundcloud

script.py

from urllib.request import urlopen
from bs4 import BeautifulSoup

name = input('Type your soundcloud username: ')

def getYourFollowingPage(yourUsername):
        followingPageUrl = 'https://soundcloud.com/' +\
                 yourUsername + '/following' 
        response = urlopen(followingPageUrl)
        page = response.read()
        return page

def getHrefs(username=name):
        page = getYourFollowingPage(username)
        soup = BeautifulSoup(page, 'html.parser')

        allLinksOnPage = soup.find_all('a')

        clearLinks = []

        for link in allLinksOnPage:
                if ('itemprop' in link.attrs):
                        dirtyHref = link.get('href')
                        cleanHref = dirtyHref[1:]
                        clearLinks.append(cleanHref)

        return clearLinks[1:]

def findFriendsOfFriends(username=name):
        result = []
        initial = getHrefs(username=name)
        for link in initial:
                result.append(getHrefs(link))
        result.append(initial)
        return result

def findCommonFriendsOfFriends(username=name):
        dict = {}
        arr = findFriendsOfFriends()
        for row in arr:
                for href in row:
                        if href != username:
                                if href not in dict:
                                        dict[href] = 1
                                else:
                                        dict[href] += 1
        return dict

#print(findCommonFriendsOfFriends())

def greaterThenOne(username=name):
        result = []
        for key, value in findCommonFriendsOfFriends().items():
                if value > 1:
                        result.append(key + ' appears ' + str(value) + ' times')

        arr = findFriendsOfFriends()
        for row in arr:
                for href in row:
                        if href != username:
                                if href not in dict:
                                        dict[href] = 1
                                else:
                                        dict[href] += 1
        return dict

#print(findCommonFriendsOfFriends())

def greaterThenOne(username=name):
        result = []
        for key, value in findCommonFriendsOfFriends().items():
                if value > 1:
                        result.append(key + ' appears ' + str(value) + ' times')

        if len(result) == 0:
                result.append('There are no first step common friends in this network')

        return result

def makeSomeOutput(username=name):
        for string in greaterThenOne():
                print(string)

makeSomeOutput()