Created
August 28, 2017 02:22
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[103. Binary Tree Zigzag Level Order Traversal] #leetcode
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class Solution { | |
public List<List<Integer>> zigzagLevelOrder(TreeNode root) { | |
Deque<TreeNode> deque = new LinkedList<>(); | |
List<List<Integer>> res = new ArrayList<List<Integer>>(); | |
if (root == null) return res; | |
deque.add(root); | |
while ( !deque.isEmpty() ) { | |
List<Integer> current = new LinkedList<>(); | |
int m = deque.size(); | |
for (int i = 0; i < m; i++) { | |
TreeNode node = deque.removeFirst(); | |
if ( res.size() % 2 == 0) { | |
// left to right | |
current.add(node.val); | |
} else { | |
// right to left | |
current.add(0, node.val); | |
} | |
if (node.left != null) deque.add(node.left); | |
if (node.right != null) deque.add(node.right); | |
} | |
res.add(current); | |
} | |
return res; | |
} | |
} |
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