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[516. Longest Palindromic Subsequence] #leetcode
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| class Solution { | |
| // O(2^n) O(n) | |
| public int longestPalindromeSubseq(String s) { | |
| return helper(0, s.length()-1, s); | |
| } | |
| private int helper(int left, int right, String s) { | |
| if (left == right) return 1; | |
| if (left > right) return 0; | |
| return s.charAt(left) == s.charAt(right) ? 2 + helper(left+1, right-1, s) : | |
| Math.max(helper(left+1, right, s), helper(left, right-1, s)); | |
| } | |
| } | |
| class Solution2 { | |
| // O(n^2) O(n^2) | |
| public int longestPalindromeSubseq(String s) { | |
| int n = s.length(); | |
| int[][] mem = new int[n][n]; | |
| for (int i = 0; i < n; i++) { | |
| for (int j = 0; j < n; j++) { | |
| mem[i][j] = -1; | |
| } | |
| } | |
| return helper(0, n-1, s, mem); | |
| } | |
| private int helper(int left, int right, String s, int[][] mem) { | |
| if (left == right) return 1; | |
| if (left > right) return 0; | |
| if (mem[left][right] != -1) return mem[left][right]; | |
| int count = s.charAt(left) == s.charAt(right) ? 2 + helper(left+1, right-1, s, mem) : | |
| Math.max(helper(left+1, right, s, mem), helper(left, right-1, s, mem)); | |
| mem[left][right] = count; | |
| return count; | |
| } | |
| } | |
| class Solution3 { | |
| public int longestPalindromeSubseq(String s) { | |
| int n = s.length(); | |
| int[][] dp = new int[n][n]; | |
| for (int i = n - 1; i >= 0; i--) { | |
| dp[i][i] = 1; | |
| for (int j = i+1; j < n; j++) { | |
| if (s.charAt(i) == s.charAt(j)) { | |
| dp[i][j] = dp[i+1][j-1] + 2; | |
| } else { | |
| dp[i][j] = Math.max(dp[i+1][j], dp[i][j-1]); | |
| } | |
| } | |
| } | |
| return dp[0][n-1]; | |
| } | |
| } |
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