Created
September 2, 2016 08:56
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Make a unary lambda function from a pointer to function/data member (C++14)
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#include <functional> | |
#include <iostream> | |
#include <utility> | |
using namespace std; | |
template<class> | |
struct memfun_traits {}; | |
template<class C, class R, class... Args> | |
struct memfun_traits<R (C::*)(Args...)> { | |
typedef C class_type; | |
typedef R return_type; | |
}; | |
template<class C, class R, class... Args> | |
struct memfun_traits<R (C::*)(Args...) const> { | |
typedef C class_type; | |
typedef R return_type; | |
}; | |
template<class> | |
struct memdat_traits {}; | |
template<class C, class T> | |
struct memdat_traits<T C::*> { | |
typedef C class_type; | |
typedef T data_type; | |
}; | |
template<class MemFun> | |
auto make_lambda_f(MemFun pf) { | |
return [pf] (typename memfun_traits<MemFun>::class_type x) { return (x.*pf)(); }; | |
} | |
template<class MemDat> | |
auto make_lambda_d(MemDat pd) { | |
return [pd] (typename memdat_traits<MemDat>::class_type x) { return x.*pd; }; | |
} | |
template<class T, class Func> | |
typename result_of<Func(T)>::type | |
do_something(T x, Func f) { | |
return f(x); | |
} | |
struct P : public pair<int, int> { | |
using pair<int, int>::pair; | |
int get_first() const { return first; } | |
int get_second() const { return second; } | |
}; | |
int func(P x) { return x.second; } | |
int main() { | |
P x(13, 42); | |
cout << do_something(x, func) << endl; | |
cout << do_something(x, [] (P x) { return x.second; }) << endl; | |
cout << do_something(x, make_lambda_d(&P::first)) << endl; | |
cout << do_something(x, make_lambda_d(&P::second)) << endl; | |
cout << do_something(x, make_lambda_f(&P::get_first)) << endl; | |
cout << do_something(x, make_lambda_f(&P::get_second)) << endl; | |
} |
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