Created
May 21, 2018 22:29
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A PeekRune method for bufio.Reader
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package jargon | |
import ( | |
"bufio" | |
"fmt" | |
"io" | |
"unicode/utf8" | |
) | |
type RuneReader struct { | |
*bufio.Reader | |
} | |
func NewRuneReader(r io.Reader) *RuneReader { | |
return &RuneReader{bufio.NewReader(r)} | |
} | |
var peekRuneBytes = []int{4, 3, 2, 1} | |
func (r *RuneReader) PeekRune() (rune, error) { | |
for peekBytes := 4; peekBytes > 0; peekBytes-- { // unicode rune can be up to 4 bytes | |
b, err := r.Peek(peekBytes) | |
if err == nil { | |
rune, _ := utf8.DecodeRune(b) | |
if rune == utf8.RuneError { | |
return rune, fmt.Errorf("Rune error") | |
} | |
// success | |
return rune, nil | |
} | |
// Otherwise, we ignore Peek errors and try the next smallest number of bytes | |
} | |
// Pretty sure we can assume EOF if we get this far | |
return -1, io.EOF | |
} | |
func TestPeekRune(t *testing.T) { | |
s := "Quick fox 世 jumped 界" | |
original := []rune(s) | |
reader := NewRuneReader(strings.NewReader(s)) | |
lasti := len(original) - 1 | |
for i := 0; i < len(original); i++ { | |
read, _, readErr := reader.ReadRune() | |
if readErr != nil { | |
t.Error(readErr) | |
} | |
if read != original[i] { | |
t.Errorf("Expect ReadRune to read %s, got %s", string(original[i]), string(read)) | |
} | |
peek, peekErr := reader.PeekRune() | |
if i == lasti { | |
// Read the last rune above, Peek should return EOF | |
if peekErr != io.EOF { | |
t.Errorf("Expected io.EOF, got %s", peekErr) | |
} | |
} | |
if i < lasti { | |
if peekErr != nil { | |
t.Error(peekErr) | |
} | |
expected := original[i+1] | |
if peek != expected { | |
t.Errorf("Expect PeekRune to get %s, got %s", string(expected), string(peek)) | |
} | |
} | |
} | |
} |
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