Sample code to read in test cases

sample.py

# On CodeEval, test cases are read in from a file which is the first argument to your program
# Open the file and read in line by line. Each line represents a different test case
# (unless given different instructions in the challenge description)

import sys

test_cases = open(sys.argv[1], 'r')

for test in test_cases:
    # ignore test if it is an empty line
    # 'test' represents the test case, do something with it
    # ...
    # ...

test_cases.close()

How to read inputs using javascript?

Bnickel's gist is no longer valid for Objective-C. Use this, and don't forget to declare your variables outside of for loops, otherwise it will throw you loads of gnuC99 errors.

#import <Foundation/Foundation.h>

int main (int argc, const char * argv[])
{
    NSAutoreleasePool* pool = [[NSAutoreleasePool alloc] init];

    // read filename from the first argument
    NSString* filename = [NSString stringWithCString:argv[1] encoding:NSASCIIStringEncoding];
    NSString* content = [NSString stringWithContentsOfFile:filename encoding:NSASCIIStringEncoding error:nil];
    NSScanner* scanner = [NSScanner scannerWithString:content];

    while (![scanner isAtEnd]) {
        NSString* line;
        [scanner scanUpToString:@"\n" intoString:&line];

        //put your code here 

        printf("%s\n", [line cStringUsingEncoding:NSASCIIStringEncoding]);
    }

    [pool release];
    return 0;
}

here is another template for Java; this works fine in my local environement, but does not work on codeeval, what is the nme of the file that is being passed as input in codeeval? couldn't find it in templates as well.

public void readByLine(){   
try{
    FileReader inputFile= new FileReader("input.txt");
    BufferedReader buffer = new BufferedReader(inputFile);

    String line;

    while((line = buffer.readLine())!= null){

        convert(line); //method to implement logic
        // System.out.println(line); //just in case you need console testing

        }

    }
    buffer.close();


}catch(FileNotFoundException ex){
    System.out.println("file not found");

}catch(IOException ex){
    System.out.println("there are some issues");

}


}

@amit000 they pass that with args so you can't hardcode the name m8

Here's my working rust version:

use std::env;
use std::error::Error;
use std::fs::File;
use std::io::BufReader;
use std::io::prelude::*;
use std::path::Path;

fn solve(s: String) {
    println!("{}", s)
}

fn main() {
    let args: Vec<_> = env::args().collect();
    let path = Path::new(&args[1]);
    let display = path.display();
    let file = match File::open(&path) {
        // The `description` method of `io::Error` returns a string that describes the error
        Err(why) => panic!("couldn't open {}: {}", display, Error::description(&why)),
        Ok(file) => file,
    };
    let reader = BufReader::new(file);
    let lines: Vec<_> = reader.lines().collect();
    for l in lines {
        solve(l.unwrap());
    }
}

I must be getting severely confused about how to run a program with input containing multiple lines. Can someone walk me through how to submit an answer for the challenge linked below? Basically sum of the lines. The actual function that would add up all of the numbers is easy enough, but I do not understand how to make my input be the different numbers from a file with multiple lines.

Working in Javascript.

https://www.codeeval.com/open_challenges/24/

What do i write as input and output filenames?

Here's some starter code for Fortran. #MakeFortranGreatAgain
program main
implicit none
character(32) :: tests
character(10) :: test
integer :: stat
!Get file name
call get_command_argument(1, arg)
!Open file
open (11,file=trim(arg),action='read')
do
!read in test
read (11,'(a)',iostat=stat) test
if (stat /= 0) exit
if (str /= '') then
.........
! Code goes here
.........
end if
end do
close (11)
end program main

Please show me an example for python3, if you need to pass a parameter to the function, how do I issue the code?