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cogumm/feedparseBOT.py

Created March 8, 2016 00:23
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feedparseBOT.py
import feedparser
def showRSS(bot, update):
rss_url = feedparser.parse("http://distrowatch.com/news/dwd.xml")
for i in range(1):
sendMessage(bot, update,
rss_url.entries[i].title + ": \n" +
rss_url.entries[i].link)
return rss_url
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