Created
February 26, 2019 20:42
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Decrypting Weak RSA...
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crypt = { "p":"7901324502264899236349230781143813838831920474669364339844939631481665770635584819958931021644265960578585153616742963330195946431321644921572803658406281", | |
"q":"12802918451444044622583757703752066118180068668479378778928741088302355425977192996799623998720429594346778865275391307730988819243843851683079000293815051", | |
"dp":"5540655028622021934429306287937775291955623308965208384582009857376053583575510784169616065113641391169613969813652523507421157045377898542386933198269451", | |
"dq": "9066897320308834206952359399737747311983309062764178906269475847173966073567988170415839954996322314157438770225952491560052871464136163421892050057498651", | |
"c":"62078086677416686867183857957350338314446280912673392448065026850212685326551183962056495964579782325302082054393933682265772802750887293602432512967994805549965020916953644635965916607925335639027579187435180607475963322465417758959002385451863122106487834784688029167720175128082066670945625067803812970871"} | |
# Chinese remainder algorithm | |
# dp = (1/e) mod (p-1) | |
# dq = (1/e) mod (q-1) | |
# qInv = (1/q) mod p | |
# | |
# m1 = c^dP mod p | |
# m2 = c^dQ mod q | |
# h = qInv * (m1 - m2) mod p | |
# m = m2 + h * q | |
# modular inverse; calculated with Euclidean Algorithm | |
def egcd(a, b): | |
if a == 0: | |
return(b, 0, 1) | |
else: | |
g, y, x = egcd(b % a, a) | |
return (g, x - (b // a) * y, y) | |
def modinv(a, m): | |
g, x, y = egcd(a, m) | |
if g != 1: | |
raise Exception('modular inverse does not exist') | |
else: | |
return x % m | |
def main(): | |
# pull values from decrypted dict | |
p = crypt["p"] | |
p = int(p) | |
q = crypt["q"] | |
q = int(q) | |
dp = crypt["dp"] | |
dp = int(dp) | |
dq = crypt["dq"] | |
dq = int(dq) | |
c = crypt["c"] | |
c = int(c) | |
# Calculate variables with chinese remainder algorithm | |
qinv = modinv(q, p) | |
m1 = pow(c, dp, p) | |
m2 = pow(c, dq, q) | |
h = (qinv * (m1 - m2)) % p | |
m = m2 + h * q | |
# print(m) | |
# Convert to hex and calculate the ASCII chars | |
hm = str(hex(m)) | |
t = hm.strip('0x') | |
#print(t) | |
sol = ''.join([chr(int(''.join(c), 16)) for c in zip(t[0::2],t[1::2])]) | |
print(sol) | |
if __name__ == "__main__": | |
main() |
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