Grab a user's Instagram feed without need for API access

instagram-rss.php

<?php
// Grab and display a user's Instagram feed without need for API access
// Replace USERNAME with username as string.
// IMPORTANT: This relies on the queryfeed.net service, which may or may not always be available

function instagramFeed() {

    // Grab and load the feed as a variable
    $user = "USERNAME";
    $feed = "https://queryfeed.net/instagram?q=" . $user;
    $rss = new DOMDocument();
    $rss->load($feed);

    // Open $images array to hold all the images and their links
    $images = array();
  
    // Loop through each 'item' of the feed
    foreach ( $rss->getElementsByTagName('item') as $node ) :
        $item = array(
          // Direct link to the image file
          'img' => $node->getElementsByTagName('enclosure')->item(0)->getAttribute('url'),
          // Link to the image's Instagram page
          'link' => $node->getElementsByTagName('link')->item(0)->nodeValue,
        );
        // Add the item to the $images array
        array_push( $images, $item );
    endforeach;
  
    // Print each item as the image file surrounded by the link to the page
    foreach ( $images as $pic ) : ?>
        <a  class="ig-feed" href="<?php echo $pic['link'] ?>">
        <img class="ig-feed" src="<?php echo $pic['img']; ?>"/>
        </a>
        <?php
    endforeach;
}