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Instagram PHP API - Working example: Load more button (AJAX)
Raw
README.markdown

Instagram PHP API

How to use

This a working example based on the previous posted workflow.
Feedback is as always welcome.

Original project repository: Instagram-PHP-API

index.php file

The index file contains the Javascript which is responsible for loading new data and a bit of PHP which displays the first results. The script makes use of jQuery's DOM data storage, to store the latest max_id.

ajax.php file

This file represents the API which delivers additional images via pagination.
It requires two GET parameters:

  • tag the tag name you used in your original request (index.php file)
  • max_id next max id

and returns a JSON object e.g.:

{
    next_id: 1340220451361,
    images: [
        "http://distilleryimage7.s3.amazonaws.com/d53ffb38bafa11e181bd12313817987b_5.jpg",
        "http://distilleryimage8.s3.amazonaws.com/647011aebaff11e188131231381b5c25_5.jpg",
        "http://distilleryimage2.s3.amazonaws.com/7206772cbaff11e1b9f1123138140926_5.jpg",
        ...
    ]
}

Example AJAX call: http://example.com/ajax.php?tag=kitty&max_id=1340220451361

Credits

Copyright (c) 2011-2012 - Programmed by Christian Metz
Released under the BSD License.

Raw
ajax.php
<?php
/**
* Instagram PHP API
*
* @link https://github.com/cosenary/Instagram-PHP-API
* @author Christian Metz
* @since 20.06.2012
*/
require 'Instagram.php';
use MetzWeb\Instagram\Instagram;
// Initialize class for public requests
$instagram = new Instagram('12345678');
// Receive AJAX request and create call object
$tag = $_GET['tag'];
$maxID = $_GET['max_id'];
$clientID = $instagram->getApiKey();
$call = new stdClass;
$call->pagination->next_max_id = $maxID;
$call->pagination->next_url = "https://api.instagram.com/v1/tags/{$tag}/media/recent?client_id={$clientID}&max_tag_id={$maxID}";
// Receive new data
$media = $instagram->pagination($call);
// Collect everything for json output
$images = array();
foreach ($media->data as $data) {
$images[] = $data->images->thumbnail->url;
}
echo json_encode(array(
'next_id' => $media->pagination->next_max_id,
'images' => $images
));
Raw
index.php
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<title>Instagram more button example</title>
<meta name="author" content="Christian Metz">
<!--
Instagram PHP API class @ Github
https://github.com/cosenary/Instagram-PHP-API
-->
<style>
article, aside, figure, footer, header, hgroup,
menu, nav, section { display: block; }
ul {
width: 950px;
}
ul > li {
float: left;
list-style: none;
padding: 4px;
}
#more {
bottom: 8px;
margin-left: 80px;
position: fixed;
font-size: 13px;
font-weight: 700;
line-height: 20px;
}
</style>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script>
$(document).ready(function() {
$('#more').click(function() {
var tag = $(this).data('tag'),
maxid = $(this).data('maxid');
$.ajax({
type: 'GET',
url: 'ajax.php',
data: {
tag: tag,
max_id: maxid
},
dataType: 'json',
cache: false,
success: function(data) {
// Output data
$.each(data.images, function(i, src) {
$('ul#photos').append('<li><img src="' + src + '"></li>');
});
// Store new maxid
$('#more').data('maxid', data.next_id);
}
});
});
});
</script>
</head>
<body>
<?php
/**
* Instagram PHP API
*
* @link https://github.com/cosenary/Instagram-PHP-API
* @author Christian Metz
* @since 20.06.2012
*/
require 'Instagram.php';
use MetzWeb\Instagram\Instagram;
// Initialize class for public requests
$instagram = new Instagram('12345678');
$tag = 'kitty';
// Get recently tagged media
$media = $instagram->getTagMedia($tag);
// Display first results in a <ul>
echo "<ul id=\"photos\">";
foreach ($media->data as $data) {
echo "<li><img src=\"{$data->images->thumbnail->url}\"></li>";
}
echo "</ul>";
// Show 'load more' button
echo "<br><button id=\"more\" data-maxid=\"{$media->pagination->next_max_id}\" data-tag=\"{$tag}\">Load more ...</button>";
?>
</body>
</html>
@sstechdevang
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Hello Respected Communicator and suppoter
I have to post a message with image on Instagram can you please share me referance link or code to solve my problem.
Thanks for your time.

Regards,
D.Gandhi

@bobber205
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bobber205 commented May 26, 2016 •
edited
Loading

@sstechdevang, this is NOW how the internet works. you can't post a generic request for help on a forum.

no one cares that much.

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