Created
September 13, 2012 11:51
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Getting coordinates without gps by cell phone
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country = 'fr' | |
device = "Nokia N95 8Gb" | |
user_agent = 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)' | |
mmap_url = 'http://www.google.com/glm/mmap' | |
geo_url = 'http://maps.google.com/maps/geo' | |
from struct import pack, unpack | |
from httplib import HTTP | |
import urllib2 | |
def fetch_latlong_http(query): | |
http = HTTP('www.google.com', 80) | |
http.putrequest('POST', '/glm/mmap') | |
http.putheader('Content-Type', 'application/binary') | |
http.putheader('Content-Length', str(len(query))) | |
http.endheaders() | |
http.send(query) | |
code, msg, headers = http.getreply() | |
result = http.file.read() | |
return result | |
def fetch_latlong_urllib(query): | |
headers = { 'User-Agent' : user_agent } | |
req = urllib2.Request(mmap_url, query, headers) | |
resp = urllib2.urlopen(req) | |
response = resp.read() | |
return response | |
fetch_latlong = fetch_latlong_http | |
def get_location_by_cell(cid, lac, mnc=0, mcc=0, country='fr'): | |
b_string = pack('>hqh2sh13sh5sh3sBiiihiiiiii', | |
21, 0, | |
len(country), country, | |
len(device), device, | |
len('1.3.1'), "1.3.1", | |
len('Web'), "Web", | |
27, 0, 0, | |
3, 0, cid, lac, | |
0, 0, 0, 0) | |
bytes = fetch_latlong(b_string) | |
(a, b,errorCode, latitude, longitude, c, d, e) = unpack(">hBiiiiih",bytes) | |
latitude = latitude / 1000000.0 | |
longitude = longitude / 1000000.0 | |
return latitude, longitude | |
def get_location_by_geo(latitude, longitude): | |
url = '%s?q=%s,%s&output=json&oe=utf8' % (geo_url, str(latitude), str(longitude)) | |
return urllib2.urlopen(url).read() | |
if __name__ == '__main__': | |
print i,get_location_by_cell(20465, 495, 3, 262) | |
print get_location_by_cell(20442, 6015) | |
print get_location_by_cell(1085, 24040) | |
print get_location_by_geo(40.714224, -73.961452) | |
print get_location_by_geo(13.749113, 100.565327) |
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