FizzBuzz from 1 to N (supplied as command-line argument) and exiting gracefully without using loops, conditionals, or segfaults - in C.

fizzbuzz_hardmode.c

#include <stdio.h>
#include <stdlib.h>

int i(const int i) { printf("%d\n", i); return i; }
int f(const int i) { printf("Fizz\n"); return i; }
int b(const int i) { printf("Buzz\n"); return i; }
int fb(const int i) { printf("FizzBuzz\n"); return i; }
int (* PC[15])(int i) = { i,i,f,i,b,f,i,i,f,b,i,f,i,i,fb }; // Printer Cycle

int go(const int arg) {
    return PC[(arg - 1) % 15](arg) + 1;
}

int stop(const int arg) {
    PC[(arg - 1) % 15](arg);
    exit(0);
}

int (* LC[2]) (int index) = { go, stop }; // Logic Cycle

void recurse(const int i, const int kill_num) {
    recurse(LC[!(i % kill_num)](i), kill_num);
}

int main(const int argc, const char *argv[]) {
    recurse(1, atoi(argv[1]));
}