Create a template within a ruby block

gistfile1.txt

ruby_block "create ssh key" do
  block do 
    k = SSHKey.generate(:type => 'RSA', :bits => 1024, :comment => "Postgres Master")
    node.set[:postgresql][:pubkey] = k.ssh_public_key
    node.save

    # Much of the DSL disappears in ruby blocks.  Here's how to create a template.
    rc = Chef::RunContext.new(node, node.cookbook_collection)
    t = Chef::Resource::Template.new "/var/lib/postgresql/.ssh/id_rsa"
    t.source("id_rsa.erb")
    t.owner("postgres")
    t.group("postgres")
    t.cookbook("postgresql")
    t.mode("0600")
    t.variables(
        :k => k.private_key
      )
    t.action(:create_if_missing)
    t.run_context=(rc)
    t.run_action("create")
  end
  not_if { File.exists?("/var/lib/postgresql/.ssh/id_rsa") }
end

Does not seem to work with chef v11.10.0 due to Chef::RunContext requiring an events argument.

@chr0n1x, here's one that works in latest Chef:

ruby_block 'run_my_template_resource' do
  action :create
  block do
    r = Chef::Resource::Template.new('template_name', run_context)
    r.path       '/path/to/write.to'
    r.source     'source.erb'
    r.cookbook   'cookbook-name'
    r.owner      'root'
    r.group      'root'
    r.mode       00600
    r.variables  my: 'variables'
    r.run_action :create
  end
end

@JeanMertz I found this while i was looking for a solution to one of my own problems with RemoteFile. By your example it feels like i should be able to do this:

ruby_block "parse-json" do
    block do
      f =  Chef::Provider::File::RemoteFile.new("/tmp/googlebackup", run_context)
      f.source "http://google.com"
      f.run_action :create
    end
    action :create
  end

but all i get is this error:

[2014-03-28T14:26:08+00:00] ERROR: ruby_block[parse-json] (/tmp/kitchen/cookbooks/jenkins_build_artefact/providers/default.rb line 16) had an error: NoMethodError: No resource or method named `source' for `Chef::Provider::RemoteFile ""'    

Any suggestions?

@mansona in my example, I instantiate the Resource instead of the Provider:

Chef::Resource::RemoteFile

This should not be used, it is not safe and breaks the Chef API.

@coderanger what should not be used exactly? Chef::Resource::RemoteFile? Or Chef::Resource::Template.new inside block? Pls be specific.

At the same time. If you are hinting not to use this approach. Please suggest an alternative

Simply stating This should not be used, it is not safe and breaks the Chef API. is good information. But it doesn't really help the OP and future observers