Created
July 17, 2015 19:40
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Luhn Algorithm in Swift
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func luhnCheck(number: String) -> Bool { | |
var sum = 0 | |
let digitStrings = reverse(number).map { String($0) } | |
for tuple in enumerate(digitStrings) { | |
if let digit = tuple.element.toInt() { | |
let odd = tuple.index % 2 == 1 | |
switch (odd, digit) { | |
case (true, 9): | |
sum += 9 | |
case (true, 0...8): | |
sum += (digit * 2) % 9 | |
default: | |
sum += digit | |
} | |
} else { | |
return false | |
} | |
} | |
return sum % 10 == 0 | |
} | |
luhnCheck("49927398716") | |
luhnCheck("49927398717") |
Swift 2:
private static func luhnCheck(cardNumber: String) -> Bool {
var sum = 0
let reversedCharacters = cardNumber.characters.reverse().map { String($0) }
for (idx, element) in reversedCharacters.enumerate() {
guard let digit = Int(element) else { return false }
switch ((idx % 2 == 1), digit) {
case (true, 9): sum += 9
case (true, 0...8): sum += (digit * 2) % 9
default: sum += digit
}
}
return sum % 10 == 0
}
Swift 3
private static func luhnCheck(cardNumber: String) -> Bool {
var sum = 0
let reversedCharacters = cardNumber.characters.reversed().map { String($0) }
for (idx, element) in reversedCharacters.enumerated() {
guard let digit = Int(element) else { return false }
switch ((idx % 2 == 1), digit) {
case (true, 9): sum += 9
case (true, 0...8): sum += (digit * 2) % 9
default: sum += digit
}
}
return sum % 10 == 0
}
Swift 4
extension String {
func luhnCheck() -> Bool {
var sum = 0
let reversedCharacters = self.reversed().map { String($0) }
for (idx, element) in reversedCharacters.enumerated() {
guard let digit = Int(element) else { return false }
switch ((idx % 2 == 1), digit) {
case (true, 9): sum += 9
case (true, 0...8): sum += (digit * 2) % 9
default: sum += digit
}
}
return sum % 10 == 0
}
}
Swift 5
private static func luhnCheck(cardNumber: String) -> Bool {
var sum = 0
let reversedCharacters = cardNumber.reversed().map { String($0) }
for (idx, element) in reversedCharacters.enumerated() {
guard let digit = Int(element) else { return false }
switch ((idx % 2 == 1), digit) {
case (true, 9): sum += 9
case (true, 0...8): sum += (digit * 2) % 9
default: sum += digit
}
}
return sum % 10 == 0
}
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Influenced by: https://gist.github.com/jonelf/bccf58698adc12e53fd6