Created
October 16, 2017 20:18
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#include <iostream> | |
#include <cmath> | |
void printArray(double **tab, size_t n, size_t k) { | |
for (size_t i = 0; i < n; i++) | |
{ | |
for (size_t j = 0; j < k; j++) | |
{ | |
std::cout << tab[i][j] << '\t'; | |
} | |
std::cout << std::endl; | |
} | |
} | |
double findMax(double **tab, size_t n, size_t k) { | |
double max = 0; | |
for (size_t i = 0; i < n; i++) | |
{ | |
for (size_t j = 0; j < k; j++) | |
{ | |
if (max < tab[i][j]) { | |
max = tab[i][j]; | |
} | |
} | |
} | |
return max; | |
} | |
int main() | |
{ | |
//metoda eliminacji guassa | |
size_t n = 3; | |
size_t k = 3; | |
double **A = new double *[n]; | |
for (size_t i = 0; i < n; i++) | |
{ | |
A[i] = new double[k]; | |
for (size_t j = 0; j < k; j++) | |
{ | |
//A[i][j] = 2.0; | |
} | |
} | |
unsigned int r = 0; | |
double max = 0; | |
A[0][0] = 3; | |
A[0][1] = -4; | |
A[0][2] = 8; | |
A[1][0] = 2; | |
A[1][1] = -1; | |
A[1][2] = 5; | |
A[2][0] = -5; | |
A[2][1] = -5; | |
A[2][2] = -15; | |
printArray(A, n, k); | |
for (size_t i = 0; i < n; i++){ | |
cou | |
} | |
/*std::cout << "max: " << findMax(A, n, k);*/ | |
return 0; | |
} |
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