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malloc()でLinuxの仮想メモリ空間のメモリ確保をし続けるだけのプログラム ref: http://qiita.com/d_shimizu/items/700e2eaf7408e7bc7a4c
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### コンパイル | |
% gcc -o get_vmem_test get_vmem_test.c | |
### 実行 | |
% ./get_vmem_test | |
122216 GB |
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### OS | |
% cat /etc/redhat-release | |
CentOS release 6.4 (Final) | |
### Kernel Version | |
% uname -r | |
2.6.32-358.11.1.el6.x86_64 | |
### Memory | |
% free | |
total used free shared buffers cached | |
Mem: 1922564 92680 1829884 0 7156 26016 | |
-/+ buffers/cache: 59508 1863056 | |
Swap: 2097144 11176 2085968 |
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#include <stdio.h> | |
#include <stdlib.h> | |
int main() { | |
char *p; | |
unsigned long i = 1073741824; | |
// 文字列変数に1GB(1073741824 B)のメモリを確保し続ける | |
// メモリを確保できなくなるとmallocはnullを返すため、nullが返されるまで繰り返す | |
do { | |
p = (char *)malloc(1073741824); | |
i=i+1073741824; | |
} while (p != NULL); | |
// iの値が確保できたメモリの総量となる(GB単位で出力) | |
printf("%lu GB \n", i/1024/1024/1024); | |
exit(0); | |
} |
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