Created
April 13, 2024 11:30
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def f(x){ // we are taking equation as x^3+x-1 | |
def f = 2*x + x - 1; | |
return f; | |
} | |
def secant(x1, x2, E) { | |
def n = 0, xm, x0, c; | |
while(true){ | |
// calculate the intermediate value | |
x0 = (x1 * f(x2) - x2 * f(x1)) / (f(x2) - f(x1)); | |
// check if x0 is root of equation or not | |
c = f(x1) * f(x0); | |
// update the value of interval | |
x1 = x2; | |
x2 = x0; | |
// update number of iteration | |
n++; | |
// if x0 is the root of equation then break the loop | |
if (c == 0) | |
break; | |
xm = (x1 * f(x2) - x2 * f(x1)) / (f(x2) - f(x1)); | |
if(Math.abs(xm - x0) >= E) continue; | |
else break; | |
} | |
// until the convergence | |
return x0.round(6) | |
//document.write("Root of the given equation=" + x0.toFixed(6)); | |
//document.write("No. of iterations = " + n); | |
} | |
response = []; | |
response["transit"] = secant(0, 10, 0.000001); | |
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