Created
February 26, 2013 01:48
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Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.
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| /** | |
| * Definition for binary tree | |
| * public class TreeNode { | |
| * int val; | |
| * TreeNode left; | |
| * TreeNode right; | |
| * TreeNode(int x) { val = x; } | |
| * } | |
| */ | |
| public class Solution { | |
| public int minDepth(TreeNode root) { | |
| // Start typing your Java solution below | |
| // DO NOT write main() function | |
| if (root == null) return 0; | |
| PriorityQueue<ArrayList<TreeNode>> que = new PriorityQueue<ArrayList<TreeNode>>(); | |
| ArrayList<TreeNode> ary = new ArrayList<TreeNode>(); | |
| ary.add(root); | |
| que.add(ary); | |
| int level = 1; | |
| while(!que.isEmpty()) { | |
| ArrayList<TreeNode> parents = que.poll(); | |
| ArrayList<TreeNode> tmp = new ArrayList<TreeNode>(); | |
| for (TreeNode parent: parents) { | |
| if (parent.left == null && parent.right == null) { | |
| return level; | |
| } | |
| if (parent.left != null) { | |
| tmp.add(parent.left); | |
| } | |
| if (parent.right != null) { | |
| tmp.add(parent.right); | |
| } | |
| } | |
| if (!tmp.isEmpty()) { | |
| que.add(tmp); | |
| level++; | |
| } | |
| } | |
| return 0; | |
| } | |
| } |
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