Quy Truong daltonnyx

Creating Neat .NET Core Command Line Apps

You can now read this on my (pretty) website! Check it out here.

Every reason to get more HackerPoints™ is a good one, so today we're going to write a neat command line app in .NET Core! The Common library has a really cool package Microsoft.Extensions.CommandlineUtils to help us parse command line arguments and structure our app, but sadly it's undocumented.

No more! In this guide, we'll explore the package and write a really neat

git filter-branch --force --commit-filter '
          if [ "$GIT_COMMITTER_EMAIL" = "[email protected]" ];
          then
                  export GIT_COMMITTER_NAME="New Name";
                  export GIT_AUTHOR_NAME="New Nam";
                  export GIT_COMMITTER_EMAIL="[email protected]";
                  export GIT_AUTHOR_EMAIL="[email protected]";
          fi;
 git commit-tree "$@"

	#!/bin/bash

	ICON_BLUETOOTH=""
	ICON_BATTERY_FULL=""
	ICON_BATTERY_THREE_QUARTERS=""
	ICON_BATTERY_HALF=""
	ICON_BATTERY_QUARTER=""
	ICON_BATTERY_EMPTY=""
	BLUETOOTH_BATTERY_STATUS=$HOME/src/scripts/bluetooth_battery_status.sh

	# PLA+ Profile
	[stepper_x]
	step_pin: PC2
	dir_pin: PB9
	enable_pin: !PC3
	microsteps: 16
	rotation_distance: 40
	endstop_pin: ^PA5
	position_endstop: 220
	position_max: 220

	#!/bin/bash
	# Sometimes you need to move your existing git repository
	# to a new remote repository (/new remote origin).
	# Here are a simple and quick steps that does exactly this.
	#
	# Let's assume we call "old repo" the repository you wish
	# to move, and "new repo" the one you wish to move to.
	#
	### Step 1. Make sure you have a local copy of all "old repo"
	### branches and tags.

	//Give level and quantity of dragon you want to merge
	//Calculate number of level 1 dragon you need to reach it.
	//Knowning merging 3 lower level dragons will get 1 dragon which has higher 1 level.
	//Merging 5 lower level will get 2 dragons which have higher 1 level.
	function numOfDragon(level, quantity) {
	if(level == 0) return 0;
	else if(level == 1) return 1 * quantity;
	if(quantity % 2 == 0) {
	return numOfDragon(level - 1, quantity / 2 * 5);
	}