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Implementation of the L algorithm for reservoir sampling
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import random | |
import numpy as np | |
from numpy.random import default_rng | |
from itertools import islice | |
def reservoir_sampling(pop, k): | |
reservoir = [] | |
stream = iter(pop) | |
for e in islice(stream, k): | |
reservoir.append(e) | |
rng = default_rng() | |
w = np.exp(np.log(rng.random()) / k) | |
nxt = (k - 1) + rng.geometric(w) | |
for i, e in enumerate(stream, k): | |
if i == nxt: | |
reservoir[rng.integers(k)] = e | |
w *= np.exp(np.log(rng.random()) / k) | |
nxt += rng.geometric(w) | |
return reservoir | |
def reservoir_sampling_with_replacement(pop, k): | |
stream = iter(pop) | |
e = next(stream) | |
reservoir = np.repeat(e, k) | |
rng = default_rng() | |
w = rng.random(k) | |
nxt = rng.geometric(w) | |
min_nxt = np.amin(nxt) | |
for i, e in enumerate(stream, 1): | |
if i == min_nxt: | |
mask = (i == nxt) | |
reservoir[mask] = e | |
w[mask] = w[mask] * rng.random(np.count_nonzero(mask)) | |
nxt[mask] = nxt[mask] + rng.geometric(w[mask]) | |
min_nxt = np.amin(nxt) | |
return reservoir.tolist() |
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