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January 22, 2018 20:40
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Increment Excel column letters
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| // Only supports positive numbers for now | |
| function column (letters, numberOfColumnsAway=0) { | |
| let newColumnLetters = letters.trim().toUpperCase() | |
| for (let i = 0; i < Math.abs(numberOfColumnsAway); i++) { | |
| newColumnLetters = incrementColumnLetters(newColumnLetters) | |
| } | |
| return newColumnLetters | |
| } | |
| function incrementColumnLetters (letters) { | |
| const INPUT_ERROR_MSG = 'Input is not a string of letters.' | |
| if (!letters) throw new TypeError(INPUT_ERROR_MSG) | |
| const startLetter = 'A' | |
| const endLetter = 'Z' | |
| const endLetterCode = endLetter.charCodeAt() | |
| const letterRangeRE = new RegExp(`[${startLetter}-${endLetter}]`,'g') | |
| const lettersList = letters.trim().toUpperCase().match(letterRangeRE) | |
| if (!Array.isArray(lettersList)) throw new TypeError(INPUT_ERROR_MSG) | |
| let i,c,letter | |
| const incrementedLettersList = [] | |
| for (i=lettersList.length-1,c=1; i>=0||c>0; i--) { | |
| if (lettersList[i]) letter = lettersList[i] | |
| else letter = startLetter, c-- | |
| if (c>0) { | |
| letter = String.fromCharCode(letter.charCodeAt() + c--) | |
| if (letter.charCodeAt() > endLetterCode) letter = startLetter, c++ | |
| } | |
| incrementedLettersList.unshift(letter) | |
| } | |
| return incrementedLettersList.join('') | |
| } |
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