My solution for returning the ordinal of a number, 2nd, 3rd, 4th

numbertoordinal.js

Array.range = (from, to, step) => Array.from(
    { length: Math.floor((to - from) / step) + 1 }, 
    (v, k) => from + k * step
);
const testArr = Array.range(0,10,1);

const modulo = (x, n) => x % n;
// Check last two digits if are certain teens
const isTeenTh = n => [10, 11, 12, 13, 14, 15, 16, 17, 18, 19].includes(n % 100)
// for ordinal 'st'
const isModRestOne = (n, by) => modulo(n, by) === 1;
// for ordinal 'nt'
const isModRestTwo = (n, by) => modulo(n, by) === 2;
// for ordinal 'rd'
const isModRestThree = (n, by) => modulo(n, by) === 3;

const getOrdinal = n => {
  if(!!isNaN(parseFloat(n)) && isFinite(n)) return NaN;
  if (isModOne(n, 10) && !isTeenTh(n)) {
    return `${n}st`;
  }  
  if (isModTwo(n, 10) && !isTeenTh(n)) {
    return `${n}nd`;
  }
  if (isModThree(n, 10) && !isTeenTh(n)) {
    return `${n}rd`;
  }  
  return n !== 0 ? `${n}th` : 0
}

const map = testArr.map((n, i) => {
  return getOrdinal(n)
})

console.log(map)