Created
March 17, 2022 20:42
-
-
Save davichoso/a94c071c528ff5a6ac1bf655cdffe3d1 to your computer and use it in GitHub Desktop.
test
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
function getNumberToLeftSide(numberToLeft) { | |
let numbr = '' | |
let i = 1; | |
while (!isNaN(numberToLeft[numberToLeft.length - i])) { | |
numbr = numberToLeft[numberToLeft.length - i] + numbr | |
i++; | |
} | |
return numbr | |
} | |
function getNumberToRightSide(numberToRight) { | |
let numbr = '' | |
let i = 0 | |
while (!isNaN(numberToRight[i])) { | |
numbr = numbr + numberToRight[i] | |
i++ | |
} | |
return numbr | |
} | |
function evalOperator(stringToEval, operator) { | |
return stringToEval.split(operator).reduce((prev, current) => { | |
const numberToLeft = getNumberToLeftSide(prev) | |
const numberToRight = getNumberToRightSide(current) | |
if (numberToLeft.length > 0 && numberToRight.length > 0) { | |
let result; | |
if (operator == '/') | |
result = numberToLeft / numberToRight | |
if (operator == '*') | |
result = numberToLeft * numberToRight | |
if (operator == '+') | |
result = (numberToLeft * 1) + (numberToRight * 1) | |
if (operator == '-') | |
result = (numberToLeft * 1) - (numberToRight * 1) | |
return prev.slice(0, -numberToLeft.length) + result + current.slice(numberToRight.length) | |
} | |
return prev + operator + current | |
}) | |
} | |
function eliminateParenthesis(str) // here we try to find last open ( | |
{ | |
let lastIndex = str.length | |
while (str.lastIndexOf('(', lastIndex) >0 ) { | |
const openIndex = str.lastIndexOf('(') // here we find the last open ( | |
const closeIndex = str.indexOf(')', openIndex) | |
let stringBetween = str.slice(openIndex + 1, closeIndex) | |
if (!isNaN(stringBetween)) { //just numbers | |
//here we try to eliminate the parenthesis | |
//console.log(str[openIndex - 1]) | |
if (openIndex > 0) { | |
const charBeforeParenthesis = str[openIndex - 1] | |
if (!isNaN(charBeforeParenthesis) || charBeforeParenthesis == ')') // if is a number or a parenthesis ad * operator | |
{ | |
stringBetween = '*' + stringBetween | |
} | |
} | |
str = str.slice(0, openIndex) + stringBetween + str.slice(closeIndex + 1) | |
// if there is a parenthesis | |
} else { | |
lastIndex = str.lastIndexOf('(')*1 -1 | |
} | |
// else the parenthesis still contains operators, do nothing | |
} | |
return str | |
} | |
function Calculator(str) { | |
// first we should evaluate posible operations | |
//while (isNaN(str)) { | |
str = evalOperator(str, '/'); | |
str = evalOperator(str, '*'); | |
str = evalOperator(str, '+'); | |
str = evalOperator(str, '-'); | |
//after we should try to eliminate parenthesis symbols | |
str = eliminateParenthesis(str); | |
//console.log(str) | |
// } | |
// code goes here | |
console.log('------------') | |
return str; | |
} | |
// keep this function call here | |
console.log(Calculator("2(6)(4/2)+(22*2)(2)")); | |
console.log(Calculator("2(6)(4/2)+(22*2)(2)")); |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment