Created
August 13, 2010 17:24
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The following iterative sequence is defined for the set of positive integers: | |
n → n/2 (n is even) | |
n → 3n + 1 (n is odd) | |
Using the rule above and starting with 13, we generate the following sequence: | |
13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1 | |
It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. | |
Which starting number, under one million, produces the longest chain? | |
implement the ruby code than answer the last question ? | |
NOTE: Once the chain starts the terms are allowed to go above one million. |
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