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@davidxkr
Created August 13, 2010 17:24
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The following iterative sequence is defined for the set of positive integers:
n → n/2 (n is even)
n → 3n + 1 (n is odd)
Using the rule above and starting with 13, we generate the following sequence:
13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1
It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms.
Which starting number, under one million, produces the longest chain?
implement the ruby code than answer the last question ?
NOTE: Once the chain starts the terms are allowed to go above one million.
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