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Save dblock/1081513 to your computer and use it in GitHub Desktop.
function( d ) { | |
// Create a copy of this date object | |
var target = new Date(d.valueOf()); | |
// ISO week date weeks start on monday | |
// so correct the day number | |
var dayNr = (d.getDay() + 6) % 7; | |
// Set the target to the thursday of this week so the | |
// target date is in the right year | |
target.setDate(target.getDate() - dayNr + 3); | |
// ISO 8601 states that week 1 is the week | |
// with january 4th in it | |
var jan4 = new Date(target.getFullYear(), 0, 4); | |
// Number of days between target date and january 4th | |
var dayDiff = (target - jan4) / 86400000; | |
// Calculate week number: Week 1 (january 4th) plus the | |
// number of weeks between target date and january 4th | |
var weekNr = 1 + Math.ceil(dayDiff / 7); | |
return weekNr; | |
} |
Heads up @ledfusion:
Your code contains an error too. Check with 1. Jan 2017 vs 2. Jan 2017. The latter returns week 2.
I'll post if I find a solution.
Edit:
The issue has been addressed at stackoverflow:
http://stackoverflow.com/a/6117889/6025684
var weekOfYear = function(date){
var d = new Date(+date);
d.setHours(0,0,0);
d.setDate(d.getDate()+4-(d.getDay()||7));
return Math.ceil((((d-new Date(d.getFullYear(),0,1))/8.64e7)+1)/7);
};
I have only performed lightweight testing; use with caution.
Tested for range:
31. Dec - 5. Jan, years 1994 (Dec) - 2019 (Jan).
Hi, what's the license? Can I reuse that code?
How could this code be adapted to include the following requirements:
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Our fiscal year begins on 1st April each year.
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Our working week begins on a Friday at 17:00 hours (don't ask lol)
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I simply want to return the week number for any year from 1st April 2016 onwards given any date of the year.
Would be very much appreciated.
Hello, there are always an exception: 31 Dec of any year is being returned wrongly as the first week of the year. It should be 52.
Working example for my case, taking straight from here:
/* For a given date, get the ISO week number
*
* Based on information at:
*
* http://www.merlyn.demon.co.uk/weekcalc.htm#WNR
*
* Algorithm is to find nearest thursday, it's year
* is the year of the week number. Then get weeks
* between that date and the first day of that year.
*
* Note that dates in one year can be weeks of previous
* or next year, overlap is up to 3 days.
*
* e.g. 2014/12/29 is Monday in week 1 of 2015
* 2012/1/1 is Sunday in week 52 of 2011
*/
function getWeekNumber(d) {
// Copy date so don't modify original
d = new Date(Date.UTC(d.getFullYear(), d.getMonth(), d.getDate()));
// Set to nearest Thursday: current date + 4 - current day number
// Make Sunday's day number 7
d.setUTCDate(d.getUTCDate() + 4 - (d.getUTCDay()||7));
// Get first day of year
var yearStart = new Date(Date.UTC(d.getUTCFullYear(),0,1));
// Calculate full weeks to nearest Thursday
var weekNo = Math.ceil(( ( (d - yearStart) / 86400000) + 1)/7);
// Return array of year and week number
return [d.getUTCFullYear(), weekNo];
}
There is an error in this code.
If Jan 4th falls on Fri/Sat/Sun, the first week of the year is "2", according to this code.
Try withnew Date(2016, 0, 1)
andnew Date(2016, 0, 4)
and you'll see that it jumps from 53 to 2I have added an if statement in the end that fixes this scenario.
Date.prototype.getWeek = function() { // Create a copy of this date object var target = new Date(this.valueOf()); // ISO week date weeks start on monday, so correct the day number var dayNr = (this.getDay() + 6) % 7; // Set the target to the thursday of this week so the // target date is in the right year target.setDate(target.getDate() - dayNr + 3); // ISO 8601 states that week 1 is the week with january 4th in it var jan4 = new Date(target.getFullYear(), 0, 4); // Number of days between target date and january 4th var dayDiff = (target - jan4) / 86400000; if(new Date(target.getFullYear(), 0, 1).getDay() < 5) { // Calculate week number: Week 1 (january 4th) plus the // number of weeks between target date and january 4th return 1 + Math.ceil(dayDiff / 7); } else { // jan 4th is on the next week (so next week is week 1) return Math.ceil(dayDiff / 7); } };
thanks you
Oh wow I just saw all these comments. Maybe someone can take this out in a JS library and write some tests?
Oh wow I just saw all these comments. Maybe someone can take this out in a JS library and write some tests?
yes, I'll try it
I have modified the code a bit.
What I want to achieve is - I want to get 2 weeks at a time. So I have made 14 instead of all 7's.
This is working fine but the problem causing is - The starting day of the week is now set to Sunday.
How can I make it back to Monday???
`Date.prototype.get2Weeks = function() {
// Create a copy of this date object
var target = new Date(this.valueOf());
// ISO week date weeks start on monday, so correct the day number
var dayNr = (this.getDay() + 6) % 14;
// Set the target to the thursday of this week so the
console.log(dayNr)
// target date is in the right year
target.setDate(target.getDate() - dayNr + 3);
// ISO 8601 states that week 1 is the week with january 4th in it
var jan4 = new Date(target.getFullYear(), 0, 4);
// Number of days between target date and january 4th
var dayDiff = (target - jan4) / 86400000;
if(new Date(target.getFullYear(), 0, 1).getDay() < 5) {
// Calculate week number: Week 1 (january 4th) plus the
// number of weeks between target date and january 4th
return 2 + Math.ceil(dayDiff / 14);
}
else { // jan 4th is on the next week (so next week is week 1)
return Math.ceil(dayDiff / 14);
}
}; `
Thank you
Anyone tried https://github.com/jsdocker/week-utils? Another library that includes this functionality? If nothing works I'll contribute this somewhere or make a new one.
There is an error in this code.
If Jan 4th falls on Fri/Sat/Sun, the first week of the year is "2", according to this code.
Try with
new Date(2016, 0, 1)
andnew Date(2016, 0, 4)
and you'll see that it jumps from 53 to 2I have added an if statement in the end that fixes this scenario.