Created
September 12, 2012 16:33
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Problematic define
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#lang racket | |
(define (f x) (cond [#f ;; or some other arbitrary computation that gives #f | |
(g x)] | |
[else x])) | |
(f 0) | |
(define (g x) x) | |
;; It is undecidable if there is an unbound identifier. |
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