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Minimal language CFA problem. Unary untyped lambda calculus. Can you get this is always true?
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;; multiplication distributes over addition test: (2 * (1 + 3)) = ((2 * 1) + (2 * 3)) | |
((lambda (plus) | |
((lambda (mult) | |
((lambda (pred) | |
((lambda (sub) | |
((lambda (church0) | |
((lambda (church1) | |
((lambda (church2) | |
((lambda (church3) | |
((lambda (true) | |
((lambda (false) | |
((lambda (church0?) | |
((lambda (Y) | |
((lambda (church=?) | |
((church=? ((mult church2) ((plus church1) church3))) | |
((plus ((mult church2) church1)) ((mult church2) church3)))) | |
(Y | |
(lambda (church=?) | |
(lambda (e1) | |
(lambda (e2) | |
(((church0? e1) ;; IF | |
(lambda (thendummy) (church0? e2))) | |
(lambda (elsedummy1) | |
(((church0? e2) ;; IF | |
false) | |
(lambda (elsedummy2) ((church=? ((sub e1) church1)) ((sub e2) church1)))))))))))) | |
(lambda (yf) | |
((lambda (yg) (yg yg)) | |
(lambda (yx) (yf (λ (yv) ((yx yx) yv)))))))) | |
(lambda (z) ((z (lambda (zx) false)) true)))) | |
(lambda (fa) (lambda (fb) (fb (lambda (bdummy) bdummy)))))) | |
(lambda (ta) (lambda (tb) (ta (lambda (adummy) adummy)))))) | |
(lambda (f3) (lambda (x3) (f3 (f3 (f3 x3))))))) | |
(lambda (f2) (lambda (x2) (f2 (f2 x2)))))) | |
(lambda (f1) (lambda (x1) (f1 x1))))) | |
(lambda (f0) (lambda (x0) x0)))) | |
(lambda (s1) | |
(lambda (s2) | |
((s2 pred) s1))))) | |
(lambda (n) | |
(lambda (rf) | |
(lambda (rx) | |
(((n (lambda (g) (lambda (h) (h (g rf))))) | |
(lambda (ignored) rx)) | |
(lambda (id) id))))))) | |
(lambda (m1) | |
(lambda (m2) | |
(lambda (mf) (m2 (m1 mf))))))) | |
(lambda (p1) | |
(lambda (p2) | |
(lambda (pf) | |
(lambda (x) ((p1 pf) ((p2 pf) x))))))) |
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