Python function to test if a file at a URL exists.

gistfile1.py

import urllib2

def file_exists(location):
    request = urllib2.Request(location)
    request.get_method = lambda : 'HEAD'
    try:
        response = urllib2.urlopen(request)
        return True
    except urllib2.HTTPError:
        return False

Updated version I wrote:

def is_urlfile(url):
    # Check if online file exists
    try:
        r = urllib.request.urlopen(url)  # response
        return r.getcode() == 200
    except urllib.request.HTTPError:
        return False

Hello ,
i wanna fetch file in server with authentication,i try this :

values = {"username": "user", "password": "password"} try: r = urllib.request.urlopen(url, values) # response return r.getcode() == 200 except urllib.request.HTTPError: return False

but thasnt work, can u help me please

For all the people saying "doesn't return anything" make sure to include a timeout in the function. I don't really know how to do it using Urllib but I know it is possible using Requests:

import requests

def is_online(url: str) -> bool:
    """
    Checks if the document at a providen URL is online.
    """
    try:
        return requests.head(url, timeout=3).status_code // 100 == 2
    except Exception:
        return False

If it still doesn't works, it might be the webserver: sometimes they simply reject HEAD requests because they are only used by bots. Instead use a GET request (replace "requests.head" to "requests.get" in the code I wrote) but note that it will also download the content body shouldn't be a problem in most cases but if its a file to download then you're kinda screwed because Python will have to load that file into memory which can take a lot of space (and that's why HEAD requests exists, but they're sometimes rejected as I said)