Created
November 29, 2021 19:30
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Annotated version of a multi-bisect algorithm finding all places where "performance became worse" in a commit list.
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| import numpy as np | |
| #perf = [10, 10, 10, 10, 9, 9, 9, 9, 9, 9, 8, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 5, 5, 5, 4, 4, 4, 4, 4, 4, 4, 4, 3, 2, 2] | |
| perf = np.concatenate([4*np.ones(25), 2*np.ones(25), np.ones(25)]) | |
| #perf = list(range(40, 0, -1)) | |
| count = 0 | |
| def worseCommit(a, b): | |
| global count | |
| count += 1 | |
| return perf[a] > perf[b] | |
| def find_true(l): | |
| ixs = [] | |
| last = l[0] | |
| for (i, e) in enumerate(l): | |
| if abs(e-last) > 0: | |
| ixs.append(i) | |
| last = e | |
| return ixs | |
| def in_section(n, a=0, b=-1): | |
| if b < 0: | |
| b = n-1 | |
| if worseCommit(a, b): # there is at least one worsening in the range. | |
| print(f'worse commit in [{a}, {b}]') | |
| if abs(b-a) == 1: # down to two commits: a better than b | |
| print(f' found! {b}') | |
| return [b] | |
| # range larger than 1 | |
| mid = int((a+b)/2) # bisect range | |
| # search in either range and merge. | |
| left = in_section(n, a, mid) | |
| right = in_section(n, mid, b) | |
| return left+right | |
| else: | |
| print(f'good commits in [{a}, {b}]') | |
| return [] | |
| print(in_section(len(perf))) | |
| print(f'took {count} calls ({len(perf)} commits)') | |
| print(find_true(perf)) |
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