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Product of all array integers except at Index
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<script id="jsbin-source-javascript" type="text/javascript"> | |
/* jshint esnext: true */ | |
let integerArr = [1, 7, 3, 4]; | |
const get_products_of_all_ints_except_at_index = (arr) => { | |
let result = []; | |
arr.forEach((crr1, index1) => { | |
let newVal = 1; | |
arr.forEach((crr2, index2) => { | |
if (crr1 != crr2) { | |
newVal *= crr2; | |
} | |
}); | |
result.push(newVal); | |
}); | |
return result; | |
}; | |
console.clear(); | |
// Challenge Problem | |
console.log(`You have an array of integers, and for each index you want to find the product of every integer except the integer at that index. Write a function get_products_of_all_ints_except_at_index() that takes an array of integers and returns an array of the products. For example, given: [1, 7, 3, 4] Your function would return: [84, 12, 28, 21] By calculating: [7*3*4, 1*3*4, 1*7*4, 1*7*3] Do not use division in your solution.`); | |
// Examples | |
console.log(get_products_of_all_ints_except_at_index([1, 7, 3, 4])); | |
console.log(get_products_of_all_ints_except_at_index([10, 3, 23, 34])); | |
</script> |
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