Nested numbers Quiz (6-10) of Udacity FEWD

quizNestedNumb.js

/*
 * Programming Quiz: Nested Numbers (6-10)
 *
 *   - The `numbers` variable is an array of arrays.
 *   - Use a nested `for` loop to cycle through `numbers`.
 *   - Convert each even number to the string "even"
 *   - Convert each odd number to the string "odd"
 */

var numbers = [
    [243, 12, 23, 12, 45, 45, 78, 66, 223, 3],
    [34, 2, 1, 553, 23, 4, 66, 23, 4, 55],
    [67, 56, 45, 553, 44, 55, 5, 428, 452, 3],
    [12, 31, 55, 445, 79, 44, 674, 224, 4, 21],
    [4, 2, 3, 52, 13, 51, 44, 1, 67, 5],
    [5, 65, 4, 5, 5, 6, 5, 43, 23, 4424],
    [74, 532, 6, 7, 35, 17, 89, 43, 43, 66],
    [53, 6, 89, 10, 23, 52, 111, 44, 109, 80],
    [67, 6, 53, 537, 2, 168, 16, 2, 1, 8],
    [76, 7, 9, 6, 3, 73, 77, 100, 56, 100]
];

// your code goes here
for (var row= 0; row < numbers.length; row++) {
    for (col= 0; col < numbers[row].length; col++) {
        if ((numbers[row][col]%2) === 0) {
            numbers[row][col]= "even"
        }
        else numbers[row][col]= "odd";
    }
}

What Went Well

• Your code should have a variable numbers
• Your code should use a nested for loop
• Your nested for loop should correctly replace all the elements in the numbers

Feedback: Your answer passed all our tests! Awesome job!

add this ;
in line 27

Make sure you line 25 into this: for (var col= 0; col < numbers[row].length; col++) {

This is a correct code:
for (var r = 0; r < numbers.length; r++) {
for (var c = 0; c < numbers[r].length; c++){
if (numbers[r][c] % 2 === 0) {
numbers[r][c] = "even";
}
else {
numbers[r][c] = "odd";
}
console.log(numbers[r][c])
}
}