Count of Digit in a 32 bit integer

CountDigit

import java.util.Arrays;
public class CountDigit {
    public static final long[] ARRAY = {
        9L,
        99L,
        999L,
        9999L,
        99999L,
        999999L,
        9999999L,
        99999999L,
        999999999L,
        9999999999L
    };

    //O(log(N) complexity
    public static int countDigit(int number){
        int count=0;
        boolean isNegative= false;
        //Storing in long in order overcome numeric overflow
        // when one will do the Math.abs on Integer.MIN_VALUE
        long longNum = number;

        if(longNum<0){
            isNegative = true;
            longNum = Math.abs(longNum);
        }

        count = Arrays.binarySearch(ARRAY,longNum);
        if(count<0){
            count = -count;
        }else{
            count = count+1;
        }

        if(isNegative){
            count++;
        }
        return count;
    }

    public static void main(String[] args){
        //Return 2
        System.out.println(countDigit(11));
        //Return 3
        System.out.println(countDigit(-11));
        //Return 1
        System.out.println(countDigit(9));
        //Return 3
        System.out.println(countDigit(-99));
        //Return 10
        System.out.println(countDigit(Integer.MAX_VALUE));
        //Return 11
        System.out.println(countDigit(Integer.MIN_VALUE));

    }
}