Given a long number, generate mnemonics using the digit-sound system, per http://www.decisionsciencenews.com/2012/01/17/some-code-to-help-you-remember-numbers/

find.py

#!/usr/bin/python
# -*- coding: utf-8 -*-
import re
from cStringIO import StringIO
from sys import argv
import random

mstr = str(argv[1])
adict = {}
wl = open('wordNum.txt')
line = wl.readline()
while line:
  m = re.match(r"(\w+)\t(\w+)\n", line)
  if m is not None:
    word = m.group(1)
    number = m.group(2)
    adict[number] = word + ' ' \
      + adict.get(number, '')
  line = wl.readline()

def rec(x, y):
  if len(x) == 0:
    return
  if x in adict:
    print x
    print adict[x]
  elif y == 1:
    p1 = x[0:len(x) / 2]
    p2 = x[len(x) / 2:len(x)]
    rec(p1, y)
    rec(p2, y)
  else:
    p1 = x[0:len(x) / 2 + 1]
    p2 = x[len(x) / 2 + 1:len(x)]
    rec(p1, y)
    rec(p2, y)

def rec3(x):
  if len(x) == 0:
    return
  if x in adict:
    print x
    print adict[x]
  else:
    maxlen = 0
    winner = ''
    for a in adict.keys():
      if a in x:
        if len(a) > maxlen:  # goes with the first
          winner = a
          maxlen = len(a)
    if maxlen > 0:
      (part1, part2) = x.split(winner, 1)
      rec3(part1)
      rec3(winner)
      rec3(part2)
    else:
      p1 = x[0:len(x) / 2 + 1]
      p2 = x[len(x) / 2 + 1:len(x)]
      rec3(p1)
      rec3(p2)

print '-----------------------'
rec(mstr, 1)
print '-----------------------'
rec(mstr, 2)
print '-----------------------'
rec3(mstr)