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didip/post-via-pycurl.py

Created September 19, 2010 18:12
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post-via-pycurl.py
c = pycurl.Curl()
c.setopt(pycurl.URL, "http://example.com/post")
c.setopt(pycurl.POST, 1)
c.setopt(pycurl.POSTFIELDS,
urllib.urlencode({
'some_data': 'the data',
'some_more_data': 'more data',
})
)
c.perform()
c.close()
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