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November 21, 2017 18:34
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Snippet útil para gerar um comando curl equivalente a um request feito com o módulo requests do python.
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| curl = lambda r: "curl -i -X {method} -H {headers} -d '{data}' '{uri}'".format(method=r.request.method, headers=" -H ".join(['"{0}: {1}"'.format(k, v) for k, v in r.request.headers.items()]), data=r.request.body if r.request.body else '', uri=r.request.url) |
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