Function check if it is a permutation of a palindrome.

PalindromeAndPermutation.swift

import Cocoa

struct CounterPalindrome {
    var countOdd = 0
    var isPermutationAndPalindrome: Bool {
        return countOdd <= 1
    }
    var table =  Dictionary<Character,Int>()
    mutating func count(_ char: Character) {
        table[char] = (table[char] ?? 0) + 1
        if(((table[char] ?? 0) % 2) == 1) {
            countOdd += 1
        } else {
            countOdd -= 1
        }
    }
}

func isPermutationAndPalindrome(str: String) -> Bool {
    let prepareStr = str.lowercased().filter({$0 != Character(" ")})
    var counter = CounterPalindrome()
    prepareStr.forEach { c in
        counter.count(c)
    }
    return counter.isPermutationAndPalindrome
}

isPermutationAndPalindrome(str: "Tact Coa")