Created
May 13, 2014 23:31
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Linear Equation Solver
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#include <iostream> | |
#include <regex> | |
#include <cstdlib> | |
using namespace std; | |
double* getInput(); | |
bool undefined(double*); | |
double a(double*); | |
double c(double*, double); | |
int main(int argc, char const* argv[]) | |
{ | |
double* input = getInput(); | |
if ( undefined(input) ) | |
cout << "Undefined\n"; | |
else | |
cout << "Output:\n" | |
<< "(" << a(input) << ", " << c(input, a(input)) << ")\n"; | |
return 0; | |
} | |
double* getInput() { | |
string rawInput; | |
static double input[4]; | |
regex nums("(\\d|\\.)+"); | |
smatch result; | |
cout << "Input:\n"; | |
cin >> rawInput; | |
sregex_iterator matches(rawInput.begin(), rawInput.end(), nums); | |
for ( int i = 0; i < 4; i++ ) { | |
result = *matches; | |
input[i] = atof( result.str().c_str() ); | |
matches++; | |
} | |
return input; | |
} | |
bool undefined(double* input) { | |
bool ans; | |
if ( input[0] == input[2] ) | |
ans = true; | |
else | |
ans = false; | |
return ans; | |
} | |
double a(double* input) { | |
return ( input[1] - input[3] ) / ( input[0] - input[2] ); | |
} | |
double c(double* input, double slope) { | |
return input[1] - slope * input[0]; | |
} |
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