Counting files with a given word using bash

counting-files.sh

#! /bin/bash

file=./folder1/folder2/file-name-input.txt

outputfile=./folder1/folder2/file-name-output.txt

while IFS= read -r cmd; do

  NUMBER_OF_FILES=$(grep --include=\*{ts,tsx} -rl './folder1' -e "$cmd" | wc -l)
  printf 'Number of ocurrences: %s - Key: %s\n' "$NUMBER_OF_FILES" "$cmd" >> $outputfile

done < "$file"

Important references that enabled me to reach the result above:

1. https://stackoverflow.com/questions/1751301/regex-match-entire-words-only
2. https://stackoverflow.com/questions/6207573/how-to-append-output-to-the-end-of-a-text-file
3. https://linuxhandbook.com/bash-printf/
4. https://stackoverflow.com/questions/4651437/how-do-i-set-a-variable-to-the-output-of-a-command-in-bash
5. https://linuxhandbook.com/if-else-bash/
6. https://stackoverflow.com/questions/4642191/read-line-by-line-in-bash-script
7. https://www.freecodecamp.org/news/shell-scripting-crash-course-how-to-write-bash-scripts-in-linux
8. https://unix.stackexchange.com/questions/6979/count-total-number-of-occurrences-using-grep